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102134441300 = 22521021344413
BaseRepresentation
bin101111100011110101…
…1111110010101010100
3100202121220222012021012
41133013223332111110
53133132404110200
6114530411311352
710243662266303
oct1370753762524
9322556865235
10102134441300
113a351258481
121796474b558
139828a98c68
144d2c71443a
1529cb806a35
hex17c7afe554

102134441300 has 18 divisors (see below), whose sum is σ = 221631737838. Its totient is φ = 40853776480.

The previous prime is 102134441249. The next prime is 102134441329. The reversal of 102134441300 is 3144431201.

It can be written as a sum of positive squares in 3 ways, for example, as 3721732036 + 98412709264 = 61006^2 + 313708^2 .

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 510672107 + ... + 510672306.

Almost surely, 2102134441300 is an apocalyptic number.

102134441300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

102134441300 is an abundant number, since it is smaller than the sum of its proper divisors (119497296538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102134441300 is a wasteful number, since it uses less digits than its factorization.

102134441300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1021344427 (or 1021344420 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 102134441300 its reverse (3144431201), we get a palindrome (105278872501).

The spelling of 102134441300 in words is "one hundred two billion, one hundred thirty-four million, four hundred forty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1021344413 2042688826 4085377652 5106722065 10213444130 20426888260 25533610325 51067220650 102134441300