Base | Representation |
---|---|
bin | 10111001111011000010110… |
… | …100111010101010110001101 |
3 | 111101220101001210111011212222 |
4 | 113033120112213111112031 |
5 | 101344120144321320023 |
6 | 1001215314421505125 |
7 | 30346400630344034 |
oct | 2717302647252615 |
9 | 441811053434788 |
10 | 102212011120013 |
11 | 2a627963685423 |
12 | b5694578721a5 |
13 | 4505722255592 |
14 | 1b35132a5771b |
15 | bc3b8043bcc8 |
hex | 5cf6169d558d |
102212011120013 has 2 divisors, whose sum is σ = 102212011120014. Its totient is φ = 102212011120012.
The previous prime is 102212011120003. The next prime is 102212011120031. The reversal of 102212011120013 is 310021110212201.
It is a happy number.
Together with next prime (102212011120031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102108660443689 + 103350676324 = 10104883^2 + 321482^2 .
It is a cyclic number.
It is not a de Polignac number, because 102212011120013 - 26 = 102212011119949 is a prime.
It is a super-2 number, since 2×1022120111200132 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 102212011119973 and 102212011120000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102212011120003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51106005560006 + 51106005560007.
It is an arithmetic number, because the mean of its divisors is an integer number (51106005560007).
Almost surely, 2102212011120013 is an apocalyptic number.
It is an amenable number.
102212011120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
102212011120013 is an equidigital number, since it uses as much as digits as its factorization.
102212011120013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 102212011120013 its reverse (310021110212201), we get a palindrome (412233121332214).
The spelling of 102212011120013 in words is "one hundred two trillion, two hundred twelve billion, eleven million, one hundred twenty thousand, thirteen".
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