102213302128997 has 2 divisors, whose sum is σ = 102213302128998. Its totient is φ = 102213302128996.

The previous prime is 102213302128979. The next prime is 102213302128999. The reversal of 102213302128997 is 799821203312201.

Together with previous prime (102213302128979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78337970563876 + 23875331565121 = 8850874^2 + 4886239^2 .

It is a cyclic number.

It is not a de Polignac number, because 102213302128997 - 2¹⁰ = 102213302127973 is a prime.

It is a super-2 number, since 2×102213302128997² (a number of 29 digits) contains 22 as substring.

Together with 102213302128999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102213302128999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51106651064498 + 51106651064499.

It is an arithmetic number, because the mean of its divisors is an integer number (51106651064499).

Almost surely, 2^{102213302128997} is an apocalyptic number.

It is an amenable number.

102213302128997 is a deficient number, since it is larger than the sum of its proper divisors (1).

102213302128997 is an equidigital number, since it uses as much as digits as its factorization.

102213302128997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 653184, while the sum is 50.

The spelling of 102213302128997 in words is "one hundred two trillion, two hundred thirteen billion, three hundred two million, one hundred twenty-eight thousand, nine hundred ninety-seven".