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10231001311 is a prime number
BaseRepresentation
bin10011000011101000…
…01011000011011111
3222102000102201100111
421201310023003133
5131423114020221
64411113510451
7511351035106
oct114164130337
928360381314
1010231001311
114380151793
121b96412427
13c7080a43b
146d0ad503d
153ed2dcbe1
hex261d0b0df

10231001311 has 2 divisors, whose sum is σ = 10231001312. Its totient is φ = 10231001310.

The previous prime is 10231001303. The next prime is 10231001351. The reversal of 10231001311 is 11310013201.

10231001311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10231001311 - 23 = 10231001303 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10231001291 and 10231001300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10231001351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115500655 + 5115500656.

It is an arithmetic number, because the mean of its divisors is an integer number (5115500656).

Almost surely, 210231001311 is an apocalyptic number.

10231001311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10231001311 is an equidigital number, since it uses as much as digits as its factorization.

10231001311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10231001311 its reverse (11310013201), we get a palindrome (21541014512).

The spelling of 10231001311 in words is "ten billion, two hundred thirty-one million, one thousand, three hundred eleven".