Base | Representation |
---|---|
bin | 10011000011111010… |
… | …00011110111001111 |
3 | 222102011211002021212 |
4 | 21201331003313033 |
5 | 131424213044101 |
6 | 4411235445035 |
7 | 511406610461 |
oct | 114175036717 |
9 | 28364732255 |
10 | 10233331151 |
11 | 43814a317a |
12 | 1b9715677b |
13 | c71144a44 |
14 | 6d1140131 |
15 | 3ed5ed1bb |
hex | 261f43dcf |
10233331151 has 2 divisors, whose sum is σ = 10233331152. Its totient is φ = 10233331150.
The previous prime is 10233331139. The next prime is 10233331153. The reversal of 10233331151 is 15113333201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10233331151 - 210 = 10233330127 is a prime.
Together with 10233331153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10233331153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5116665575 + 5116665576.
It is an arithmetic number, because the mean of its divisors is an integer number (5116665576).
Almost surely, 210233331151 is an apocalyptic number.
10233331151 is a deficient number, since it is larger than the sum of its proper divisors (1).
10233331151 is an equidigital number, since it uses as much as digits as its factorization.
10233331151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 10233331151 its reverse (15113333201), we get a palindrome (25346664352).
The spelling of 10233331151 in words is "ten billion, two hundred thirty-three million, three hundred thirty-one thousand, one hundred fifty-one".
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