10241223354431 has 2 divisors, whose sum is σ = 10241223354432. Its totient is φ = 10241223354430.

The previous prime is 10241223354413. The next prime is 10241223354433. The reversal of 10241223354431 is 13445332214201.

Together with previous prime (10241223354413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10241223354431 - 2¹⁰ = 10241223353407 is a prime.

It is a super-2 number, since 2×10241223354431² (a number of 27 digits) contains 22 as substring.

Together with 10241223354433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10241223354391 and 10241223354400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10241223354433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5120611677215 + 5120611677216.

It is an arithmetic number, because the mean of its divisors is an integer number (5120611677216).

Almost surely, 2^{10241223354431} is an apocalyptic number.

10241223354431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10241223354431 is an equidigital number, since it uses as much as digits as its factorization.

10241223354431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 10241223354431 its reverse (13445332214201), we get a palindrome (23686555568632).

The spelling of 10241223354431 in words is "ten trillion, two hundred forty-one billion, two hundred twenty-three million, three hundred fifty-four thousand, four hundred thirty-one".