Base | Representation |
---|---|
bin | 11101110101110010100… |
… | …00001011100111101111 |
3 | 10122000111122010000002222 |
4 | 32322321100023213233 |
5 | 113244313410241221 |
6 | 2103004312505555 |
7 | 134035100161604 |
oct | 16727120134757 |
9 | 3560448100088 |
10 | 1025310243311 |
11 | 3659169a2352 |
12 | 1468663ab2bb |
13 | 758bcb78383 |
14 | 378a7aac6ab |
15 | 1ba0d7bc9ab |
hex | eeb940b9ef |
1025310243311 has 2 divisors, whose sum is σ = 1025310243312. Its totient is φ = 1025310243310.
The previous prime is 1025310243283. The next prime is 1025310243341. The reversal of 1025310243311 is 1133420135201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1025310243311 - 210 = 1025310242287 is a prime.
It is a super-2 number, since 2×10253102433112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1025310243341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 512655121655 + 512655121656.
It is an arithmetic number, because the mean of its divisors is an integer number (512655121656).
Almost surely, 21025310243311 is an apocalyptic number.
1025310243311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1025310243311 is an equidigital number, since it uses as much as digits as its factorization.
1025310243311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 1025310243311 its reverse (1133420135201), we get a palindrome (2158730378512).
It can be divided in two parts, 1025310 and 243311, that added together give a palindrome (1268621).
The spelling of 1025310243311 in words is "one trillion, twenty-five billion, three hundred ten million, two hundred forty-three thousand, three hundred eleven".
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