1025310243341 has 2 divisors, whose sum is σ = 1025310243342. Its totient is φ = 1025310243340.

The previous prime is 1025310243311. The next prime is 1025310243343. The reversal of 1025310243341 is 1433420135201.

1025310243341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 645057954025 + 380252289316 = 803155^2 + 616646^2 .

It is a cyclic number.

It is not a de Polignac number, because 1025310243341 - 2²⁶ = 1025243134477 is a prime.

It is a super-2 number, since 2×1025310243341² (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1025310243343, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1025310243343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 512655121670 + 512655121671.

It is an arithmetic number, because the mean of its divisors is an integer number (512655121671).

Almost surely, 2^{1025310243341} is an apocalyptic number.

It is an amenable number.

1025310243341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1025310243341 is an equidigital number, since it uses as much as digits as its factorization.

1025310243341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1025310243341 its reverse (1433420135201), we get a palindrome (2458730378542).

The spelling of 1025310243341 in words is "one trillion, twenty-five billion, three hundred ten million, two hundred forty-three thousand, three hundred forty-one".