1030203304035 has 48 divisors (see below), whose sum is σ = 1754980972800. Its totient is φ = 515942751744.

The previous prime is 1030203304003. The next prime is 1030203304073. The reversal of 1030203304035 is 5304033020301.

It is a happy number.

It is not a de Polignac number, because 1030203304035 - 2⁵ = 1030203304003 is a prime.

It is a super-4 number, since 4×1030203304035⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1030203303996 and 1030203304014.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1632396 + ... + 2173734.

It is an arithmetic number, because the mean of its divisors is an integer number (36562103600).

Almost surely, 2^{1030203304035} is an apocalyptic number.

1030203304035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1030203304035 is a deficient number, since it is larger than the sum of its proper divisors (724777668765).

1030203304035 is a wasteful number, since it uses less digits than its factorization.

1030203304035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 541820 (or 541803 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 24.

Adding to 1030203304035 its reverse (5304033020301), we get a palindrome (6334236324336).

The spelling of 1030203304035 in words is "one trillion, thirty billion, two hundred three million, three hundred four thousand, thirty-five".