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1030220121300 = 22352103137397613
BaseRepresentation
bin11101111110111011110…
…01111000010011010100
310122111011210220122111220
432333131321320103110
5113334342322340200
62105135424330340
7134300546354646
oct16773571702324
93574153818456
101030220121300
11367a06445357
121477b67739b0
13761c3141616
1437c11bd0896
151bbe98714a0
hexefdde784d4

1030220121300 has 288 divisors, whose sum is σ = 3044272987392. Its totient is φ = 268952555520.

The previous prime is 1030220121277. The next prime is 1030220121313. The reversal of 1030220121300 is 31210220301.

It is a super-2 number, since 2×10302201213002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1030220121300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1680619794 + ... + 1680620406.

Almost surely, 21030220121300 is an apocalyptic number.

1030220121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1030220121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1522136493696).

1030220121300 is an abundant number, since it is smaller than the sum of its proper divisors (2014052866092).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1030220121300 is a wasteful number, since it uses less digits than its factorization.

1030220121300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1267 (or 1260 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1030220121300 its reverse (31210220301), we get a palindrome (1061430341601).

Subtracting from 1030220121300 its reverse (31210220301), we obtain a palindrome (999009900999).

The spelling of 1030220121300 in words is "one trillion, thirty billion, two hundred twenty million, one hundred twenty-one thousand, three hundred".