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103023051311 = 1011020030211
BaseRepresentation
bin101111111110010100…
…1110000001000101111
3100211220212001021001002
41133330221300020233
53141442400120221
6115154513310515
710305002326115
oct1377451601057
9324825037032
10103023051311
113a767910314
1217b7226543b
13993ac051bb
144db4747ab5
152a2e83380b
hex17fca7022f

103023051311 has 4 divisors (see below), whose sum is σ = 104043081624. Its totient is φ = 102003021000.

The previous prime is 103023051269. The next prime is 103023051353. The reversal of 103023051311 is 113150320301.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (103023051269) and next prime (103023051353).

It is a cyclic number.

It is not a de Polignac number, because 103023051311 - 218 = 103022789167 is a prime.

It is a super-2 number, since 2×1030230513112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103023054311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 510015005 + ... + 510015206.

It is an arithmetic number, because the mean of its divisors is an integer number (26010770406).

Almost surely, 2103023051311 is an apocalyptic number.

103023051311 is a deficient number, since it is larger than the sum of its proper divisors (1020030313).

103023051311 is a wasteful number, since it uses less digits than its factorization.

103023051311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1020030312.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 103023051311 its reverse (113150320301), we get a palindrome (216173371612).

The spelling of 103023051311 in words is "one hundred three billion, twenty-three million, fifty-one thousand, three hundred eleven".

Divisors: 1 101 1020030211 103023051311