Search a number
-
+
10303300125 = 32539158489
BaseRepresentation
bin10011001100001111…
…11110001000011101
3222121001110212200100
421212013332020131
5132100121101000
64422215251313
7513216414606
oct114607761035
928531425610
1010303300125
114407a42978
121bb6679b39
13c827a23c1
146da554dad
1540481ea00
hex2661fe21d

10303300125 has 24 divisors (see below), whose sum is σ = 18573417720. Its totient is φ = 5495092800.

The previous prime is 10303300121. The next prime is 10303300129. The reversal of 10303300125 is 52100330301.

10303300125 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (10303300121) and next prime (10303300129).

It can be written as a sum of positive squares in 4 ways, for example, as 906130404 + 9397169721 = 30102^2 + 96939^2 .

It is not a de Polignac number, because 10303300125 - 22 = 10303300121 is a prime.

It is a super-3 number, since 3×103033001253 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10303300098 and 10303300107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10303300121) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4578120 + ... + 4580369.

It is an arithmetic number, because the mean of its divisors is an integer number (773892405).

Almost surely, 210303300125 is an apocalyptic number.

10303300125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

10303300125 is a deficient number, since it is larger than the sum of its proper divisors (8270117595).

10303300125 is an equidigital number, since it uses as much as digits as its factorization.

10303300125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9158510 (or 9158497 counting only the distinct ones).

The product of its (nonzero) digits is 270, while the sum is 18.

Adding to 10303300125 its reverse (52100330301), we get a palindrome (62403630426).

The spelling of 10303300125 in words is "ten billion, three hundred three million, three hundred thousand, one hundred twenty-five".

Divisors: 1 3 5 9 15 25 45 75 125 225 375 1125 9158489 27475467 45792445 82426401 137377335 228962225 412132005 686886675 1144811125 2060660025 3434433375 10303300125