103040117 has 4 divisors (see below), whose sum is σ = 103071276. Its totient is φ = 103008960.

The previous prime is 103040087. The next prime is 103040149. The reversal of 103040117 is 711040301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 711040301 = 1187 ⋅599023.

It can be written as a sum of positive squares in 2 ways, for example, as 60124516 + 42915601 = 7754^2 + 6551^2 .

It is a cyclic number.

It is not a de Polignac number, because 103040117 - 2¹⁰ = 103039093 is a prime.

It is a super-2 number, since 2×103040117² = 21234531422747378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103040095 and 103040104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103040167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9938 + ... + 17459.

It is an arithmetic number, because the mean of its divisors is an integer number (25767819).

Almost surely, 2^103040117 is an apocalyptic number.

It is an amenable number.

103040117 is a deficient number, since it is larger than the sum of its proper divisors (31159).

103040117 is an equidigital number, since it uses as much as digits as its factorization.

103040117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31158.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 103040117 is about 10150.8677954153. The cubic root of 103040117 is about 468.8156645906.

Adding to 103040117 its reverse (711040301), we get a palindrome (814080418).

The spelling of 103040117 in words is "one hundred three million, forty thousand, one hundred seventeen".