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10304454413 = 11936768583
BaseRepresentation
bin10011001100011000…
…10111111100001101
3222121010122112001202
421212030113330031
5132100420020123
64422300115245
7513232263101
oct114614277415
928533575052
1010304454413
114408661130
121bb6b35b25
13c82ab7906
146da775901
1540499ba28
hex266317f0d

10304454413 has 4 divisors (see below), whose sum is σ = 11241223008. Its totient is φ = 9367685820.

The previous prime is 10304454403. The next prime is 10304454427. The reversal of 10304454413 is 31445440301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10304454413 - 24 = 10304454397 is a prime.

It is a super-3 number, since 3×103044544133 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10304454403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468384281 + ... + 468384302.

It is an arithmetic number, because the mean of its divisors is an integer number (2810305752).

Almost surely, 210304454413 is an apocalyptic number.

It is an amenable number.

10304454413 is a deficient number, since it is larger than the sum of its proper divisors (936768595).

10304454413 is an equidigital number, since it uses as much as digits as its factorization.

10304454413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 936768594.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 10304454413 its reverse (31445440301), we get a palindrome (41749894714).

The spelling of 10304454413 in words is "ten billion, three hundred four million, four hundred fifty-four thousand, four hundred thirteen".

Divisors: 1 11 936768583 10304454413