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103100013223 is a prime number
BaseRepresentation
bin110000000000100111…
…1010101101010100111
3100212010012212022221021
41200001033111222213
53142122100410343
6115210303032011
710306625436634
oct1400117255247
9325105768837
10103100013223
113a7a72a69a9
1217b93b9b607
139950b407ac
144dc0a5d18b
152a364870ed
hex18013d5aa7

103100013223 has 2 divisors, whose sum is σ = 103100013224. Its totient is φ = 103100013222.

The previous prime is 103100013197. The next prime is 103100013239. The reversal of 103100013223 is 322310001301.

It is an a-pointer prime, because the next prime (103100013239) can be obtained adding 103100013223 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103100013223 - 213 = 103100005031 is a prime.

It is a super-2 number, since 2×1031000132232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103100013197 and 103100013206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103100023223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550006611 + 51550006612.

It is an arithmetic number, because the mean of its divisors is an integer number (51550006612).

Almost surely, 2103100013223 is an apocalyptic number.

103100013223 is a deficient number, since it is larger than the sum of its proper divisors (1).

103100013223 is an equidigital number, since it uses as much as digits as its factorization.

103100013223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 103100013223 its reverse (322310001301), we get a palindrome (425410014524).

The spelling of 103100013223 in words is "one hundred three billion, one hundred million, thirteen thousand, two hundred twenty-three".