1031001001411 has 2 divisors, whose sum is σ = 1031001001412. Its totient is φ = 1031001001410.

The previous prime is 1031001001409. The next prime is 1031001001417. The reversal of 1031001001411 is 1141001001301.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1031001001411 - 2¹ = 1031001001409 is a prime.

Together with 1031001001409, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1031001001391 and 1031001001400.

It is not a weakly prime, because it can be changed into another prime (1031001001417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515500500705 + 515500500706.

It is an arithmetic number, because the mean of its divisors is an integer number (515500500706).

Almost surely, 2^{1031001001411} is an apocalyptic number.

1031001001411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031001001411 is an equidigital number, since it uses as much as digits as its factorization.

1031001001411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1031001001411 its reverse (1141001001301), we get a palindrome (2172002002712).

The spelling of 1031001001411 in words is "one trillion, thirty-one billion, one million, one thousand, four hundred eleven".