10311311312413 has 4 divisors (see below), whose sum is σ = 10325494684960. Its totient is φ = 10297127939868.

The previous prime is 10311311312411. The next prime is 10311311312483. The reversal of 10311311312413 is 31421311311301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10311311312413 - 2¹ = 10311311312411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10311311312411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7091685183 + ... + 7091686636.

It is an arithmetic number, because the mean of its divisors is an integer number (2581373671240).

Almost surely, 2^{10311311312413} is an apocalyptic number.

It is an amenable number.

10311311312413 is a deficient number, since it is larger than the sum of its proper divisors (14183372547).

10311311312413 is an equidigital number, since it uses as much as digits as its factorization.

10311311312413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14183372546.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 10311311312413 its reverse (31421311311301), we get a palindrome (41732622623714).

The spelling of 10311311312413 in words is "ten trillion, three hundred eleven billion, three hundred eleven million, three hundred twelve thousand, four hundred thirteen".