Base | Representation |
---|---|
bin | 10011001101001101… |
… | …00100110111111011 |
3 | 222121121120111011201 |
4 | 21212212210313323 |
5 | 132104144320011 |
6 | 4423103235031 |
7 | 513344541364 |
oct | 114646446773 |
9 | 28547514151 |
10 | 10311323131 |
11 | 441152275a |
12 | 1bb92a8a77 |
13 | c84351145 |
14 | 6db642b6b |
15 | 4053a6cc1 |
hex | 2669a4dfb |
10311323131 has 8 divisors (see below), whose sum is σ = 10785958560. Its totient is φ = 9838880832.
The previous prime is 10311323119. The next prime is 10311323153. The reversal of 10311323131 is 13132311301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10311323131 - 213 = 10311314939 is a prime.
It is a super-2 number, since 2×103113231312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10311323099 and 10311323108.
It is not an unprimeable number, because it can be changed into a prime (10311323101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 538660 + ... + 557473.
It is an arithmetic number, because the mean of its divisors is an integer number (1348244820).
Almost surely, 210311323131 is an apocalyptic number.
10311323131 is a deficient number, since it is larger than the sum of its proper divisors (474635429).
10311323131 is a wasteful number, since it uses less digits than its factorization.
10311323131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1096565.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 10311323131 its reverse (13132311301), we get a palindrome (23443634432).
The spelling of 10311323131 in words is "ten billion, three hundred eleven million, three hundred twenty-three thousand, one hundred thirty-one".
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