1031211134320 has 160 divisors (see below), whose sum is σ = 2456181294336. Its totient is φ = 402526924800.

The previous prime is 1031211134311. The next prime is 1031211134323. The reversal of 1031211134320 is 234311121301.

It is a junction number, because it is equal to n+sod(n) for n = 1031211134291 and 1031211134300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031211134323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 618602127 + ... + 618603793.

Almost surely, 2^{1031211134320} is an apocalyptic number.

1031211134320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1031211134320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1228090647168).

1031211134320 is an abundant number, since it is smaller than the sum of its proper divisors (1424970160016).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1031211134320 is a wasteful number, since it uses less digits than its factorization.

1031211134320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2759 (or 2753 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1031211134320 its reverse (234311121301), we get a palindrome (1265522255621).

The spelling of 1031211134320 in words is "one trillion, thirty-one billion, two hundred eleven million, one hundred thirty-four thousand, three hundred twenty".