Base | Representation |
---|---|
bin | 11110000000110001111… |
… | …10111011100100001101 |
3 | 10122120201212222210122002 |
4 | 33000120332323210031 |
5 | 113343410043114013 |
6 | 2105422033002045 |
7 | 134334243302036 |
oct | 17003076734415 |
9 | 3576655883562 |
10 | 1031211301133 |
11 | 368374994442 |
12 | 147a326b3325 |
13 | 763205b0c70 |
14 | 37ca76c3a8d |
15 | 1bc568ae358 |
hex | f018fbb90d |
1031211301133 has 8 divisors (see below), whose sum is σ = 1168984471200. Its totient is φ = 901788020208.
The previous prime is 1031211301129. The next prime is 1031211301177. The reversal of 1031211301133 is 3311031121301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1031211301133 - 22 = 1031211301129 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031211301193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2087472023 + ... + 2087472516.
It is an arithmetic number, because the mean of its divisors is an integer number (146123058900).
Almost surely, 21031211301133 is an apocalyptic number.
1031211301133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1031211301133 is a deficient number, since it is larger than the sum of its proper divisors (137773170067).
1031211301133 is a wasteful number, since it uses less digits than its factorization.
1031211301133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4174944571.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1031211301133 its reverse (3311031121301), we get a palindrome (4342242422434).
The spelling of 1031211301133 in words is "one trillion, thirty-one billion, two hundred eleven million, three hundred one thousand, one hundred thirty-three".
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