Base | Representation |
---|---|
bin | 10111011100100111000111… |
… | …110111100111001101111101 |
3 | 111112010021220100011000012011 |
4 | 113130213013313213031331 |
5 | 102004014231100213310 |
6 | 1003153122541011221 |
7 | 30502156016306416 |
oct | 2734470767471575 |
9 | 445107810130164 |
10 | 103121223054205 |
11 | 2a94851305a774 |
12 | b695700b53b11 |
13 | 457039c367005 |
14 | 1b6714566280d |
15 | bdc64655a78a |
hex | 5dc9c7de737d |
103121223054205 has 16 divisors (see below), whose sum is σ = 125321536120320. Its totient is φ = 81446427309312.
The previous prime is 103121223054193. The next prime is 103121223054211. The reversal of 103121223054205 is 502450322121301.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 103121223054205 - 27 = 103121223054077 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4944604 + ... + 15188533.
It is an arithmetic number, because the mean of its divisors is an integer number (7832596007520).
Almost surely, 2103121223054205 is an apocalyptic number.
It is an amenable number.
103121223054205 is a deficient number, since it is larger than the sum of its proper divisors (22200313066115).
103121223054205 is a wasteful number, since it uses less digits than its factorization.
103121223054205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20146188.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 103121223054205 its reverse (502450322121301), we get a palindrome (605571545175506).
The spelling of 103121223054205 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred twenty-three million, fifty-four thousand, two hundred five".
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