103125114014133 has 8 divisors (see below), whose sum is σ = 137503009713600. Its totient is φ = 68748647162048.

The previous prime is 103125114014077. The next prime is 103125114014161. The reversal of 103125114014133 is 331410411521301.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-103125114014133 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 103125114014133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103125114014233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 357043428 + ... + 357332141.

It is an arithmetic number, because the mean of its divisors is an integer number (17187876214200).

Almost surely, 2^{103125114014133} is an apocalyptic number.

It is an amenable number.

103125114014133 is a deficient number, since it is larger than the sum of its proper divisors (34377895699467).

103125114014133 is an equidigital number, since it uses as much as digits as its factorization.

103125114014133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 714423691.

The product of its (nonzero) digits is 4320, while the sum is 30.

Adding to 103125114014133 its reverse (331410411521301), we get a palindrome (434535525535434).

The spelling of 103125114014133 in words is "one hundred three trillion, one hundred twenty-five billion, one hundred fourteen million, fourteen thousand, one hundred thirty-three".