1031420143 has 4 divisors (see below), whose sum is σ = 1110760168. Its totient is φ = 952080120.

The previous prime is 1031420113. The next prime is 1031420161. The reversal of 1031420143 is 3410241301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3410241301 = 9521 ⋅358181.

It is a cyclic number.

It is not a de Polignac number, because 1031420143 - 2¹³ = 1031411951 is a prime.

It is a super-2 number, since 2×1031420143² = 2127655022772280898, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1031420143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031420113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39669993 + ... + 39670018.

It is an arithmetic number, because the mean of its divisors is an integer number (277690042).

Almost surely, 2^1031420143 is an apocalyptic number.

1031420143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1031420143 is a deficient number, since it is larger than the sum of its proper divisors (79340025).

1031420143 is an equidigital number, since it uses as much as digits as its factorization.

1031420143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79340024.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 1031420143 is about 32115.7304603212. The cubic root of 1031420143 is about 1010.3655648234.

Adding to 1031420143 its reverse (3410241301), we get a palindrome (4441661444).

The spelling of 1031420143 in words is "one billion, thirty-one million, four hundred twenty thousand, one hundred forty-three".