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103202112300 = 223527148733049
BaseRepresentation
bin110000000011101010…
…0110100001100101100
3100212101022222111112120
41200013110310030230
53142324220043200
6115224351232540
710312305323610
oct1400724641454
9325338874476
10103202112300
113a8499a1501
1218002218750
13996903a851
144dd0439340
152a404039a0
hex180753432c

103202112300 has 144 divisors (see below), whose sum is σ = 341494809600. Its totient is φ = 23572477440.

The previous prime is 103202112271. The next prime is 103202112301. The reversal of 103202112300 is 3211202301.

It is a super-2 number, since 2×1032021123002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 103202112300.

It is not an unprimeable number, because it can be changed into a prime (103202112301) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3106176 + ... + 3139224.

Almost surely, 2103202112300 is an apocalyptic number.

103202112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 103202112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170747404800).

103202112300 is an abundant number, since it is smaller than the sum of its proper divisors (238292697300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103202112300 is a wasteful number, since it uses less digits than its factorization.

103202112300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34560 (or 34553 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 103202112300 its reverse (3211202301), we get a palindrome (106413314601).

Subtracting from 103202112300 its reverse (3211202301), we obtain a palindrome (99990909999).

The spelling of 103202112300 in words is "one hundred three billion, two hundred two million, one hundred twelve thousand, three hundred".

Divisors: 1 2 3 4 5 6 7 10 12 14 15 20 21 25 28 30 35 42 50 60 70 75 84 100 105 140 150 175 210 300 350 420 525 700 1050 1487 2100 2974 4461 5948 7435 8922 10409 14870 17844 20818 22305 29740 31227 33049 37175 41636 44610 52045 62454 66098 74350 89220 99147 104090 111525 124908 132196 148700 156135 165245 198294 208180 223050 231343 260225 312270 330490 396588 446100 462686 495735 520450 624540 660980 694029 780675 826225 925372 991470 1040900 1156715 1388058 1561350 1652450 1982940 2313430 2478675 2776116 3122700 3304900 3470145 4626860 4957350 5783575 6940290 9914700 11567150 13880580 17350725 23134300 34701450 49143863 69402900 98287726 147431589 196575452 245719315 294863178 344007041 491438630 589726356 688014082 737157945 982877260 1032021123 1228596575 1376028164 1474315890 1720035205 2064042246 2457193150 2948631780 3440070410 3685789725 4128084492 4914386300 5160105615 6880140820 7371579450 8600176025 10320211230 14743158900 17200352050 20640422460 25800528075 34400704100 51601056150 103202112300