Base | Representation |
---|---|
bin | 110000000101000110… |
… | …1000010011111010111 |
3 | 100212111200212001010111 |
4 | 1200022031002133113 |
5 | 3142424100432320 |
6 | 115233234303451 |
7 | 10313432651620 |
oct | 1401215023727 |
9 | 325450761114 |
10 | 103250405335 |
11 | 3a874186800 |
12 | 18016427b87 |
13 | 9976048ccc |
14 | 4dd6a0aa47 |
15 | 2a44792a5a |
hex | 180a3427d7 |
103250405335 has 48 divisors (see below), whose sum is σ = 164799206208. Its totient is φ = 60577735680.
The previous prime is 103250405333. The next prime is 103250405339. The reversal of 103250405335 is 533504052301.
It is not a de Polignac number, because 103250405335 - 21 = 103250405333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103250405297 and 103250405306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103250405333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 645072 + ... + 789061.
It is an arithmetic number, because the mean of its divisors is an integer number (3433316796).
Almost surely, 2103250405335 is an apocalyptic number.
103250405335 is a deficient number, since it is larger than the sum of its proper divisors (61548800873).
103250405335 is a wasteful number, since it uses less digits than its factorization.
103250405335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1434184 (or 1434173 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 103250405335 its reverse (533504052301), we get a palindrome (636754457636).
The spelling of 103250405335 in words is "one hundred three billion, two hundred fifty million, four hundred five thousand, three hundred thirty-five".
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