103313111302 has 4 divisors (see below), whose sum is σ = 154969666956. Its totient is φ = 51656555650.

The previous prime is 103313111299. The next prime is 103313111309. The reversal of 103313111302 is 203111313301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 203111313301 = 13 ⋅15623947177.

It is a self number, because there is not a number n which added to its sum of digits gives 103313111302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103313111309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25828277824 + ... + 25828277827.

It is an arithmetic number, because the mean of its divisors is an integer number (38742416739).

Almost surely, 2^103313111302 is an apocalyptic number.

103313111302 is a deficient number, since it is larger than the sum of its proper divisors (51656555654).

103313111302 is an equidigital number, since it uses as much as digits as its factorization.

103313111302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51656555653.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 103313111302 its reverse (203111313301), we get a palindrome (306424424603).

The spelling of 103313111302 in words is "one hundred three billion, three hundred thirteen million, one hundred eleven thousand, three hundred two".