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10334213102 = 25167106551
BaseRepresentation
bin10011001111111011…
…11001001111101110
3222200012122102022102
421213331321033232
5132131024304402
64425242015102
7514043235113
oct114775711756
928605572272
1010334213102
114423437294
122004aa7492
13c89006ac5
147006c090a
154073c9102
hex267f793ee

10334213102 has 4 divisors (see below), whose sum is σ = 15501319656. Its totient is φ = 5167106550.

The previous prime is 10334213101. The next prime is 10334213137. The reversal of 10334213102 is 20131243301.

10334213102 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20131243301 = 131548557177.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10334213101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2583553274 + ... + 2583553277.

It is an arithmetic number, because the mean of its divisors is an integer number (3875329914).

Almost surely, 210334213102 is an apocalyptic number.

10334213102 is a deficient number, since it is larger than the sum of its proper divisors (5167106554).

10334213102 is an equidigital number, since it uses as much as digits as its factorization.

10334213102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5167106553.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 10334213102 its reverse (20131243301), we get a palindrome (30465456403).

The spelling of 10334213102 in words is "ten billion, three hundred thirty-four million, two hundred thirteen thousand, one hundred two".

Divisors: 1 2 5167106551 10334213102