Base | Representation |
---|---|
bin | 1001011001100101010010… |
… | …0111101010111111110111 |
3 | 1100121000201122200212221221 |
4 | 2112121110213222333313 |
5 | 2323312301404000210 |
6 | 33551515012451211 |
7 | 2114454454011412 |
oct | 226312447527767 |
9 | 40530648625857 |
10 | 10335111000055 |
11 | 33251067a6336 |
12 | 11ab01b919b07 |
13 | 59c79b1a33ba |
14 | 27a3173d2b79 |
15 | 12dc8ecab1da |
hex | 966549eaff7 |
10335111000055 has 4 divisors (see below), whose sum is σ = 12402133200072. Its totient is φ = 8268088800040.
The previous prime is 10335111000017. The next prime is 10335111000139. The reversal of 10335111000055 is 55000011153301.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 10335111000055 - 221 = 10335108902903 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10335110999993 and 10335111000029.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1033511100001 + ... + 1033511100010.
It is an arithmetic number, because the mean of its divisors is an integer number (3100533300018).
Almost surely, 210335111000055 is an apocalyptic number.
10335111000055 is a deficient number, since it is larger than the sum of its proper divisors (2067022200017).
10335111000055 is an equidigital number, since it uses as much as digits as its factorization.
10335111000055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2067022200016.
The product of its (nonzero) digits is 1125, while the sum is 25.
Adding to 10335111000055 its reverse (55000011153301), we get a palindrome (65335122153356).
The spelling of 10335111000055 in words is "ten trillion, three hundred thirty-five billion, one hundred eleven million, fifty-five", and thus it is an aban number.
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