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10340512151 is a prime number
BaseRepresentation
bin10011010000101011…
…11011000110010111
3222200122111102222112
421220111323012113
5132134132342101
64430025021235
7514150621514
oct115025730627
928618442875
1010340512151
114426a49912
12200702481b
13c8a400c58
1470148030b
15407c206bb
hex26857b197

10340512151 has 2 divisors, whose sum is σ = 10340512152. Its totient is φ = 10340512150.

The previous prime is 10340512121. The next prime is 10340512153. The reversal of 10340512151 is 15121504301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10340512151 - 218 = 10340250007 is a prime.

It is a super-3 number, since 3×103405121513 (a number of 31 digits) contains 333 as substring.

Together with 10340512153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10340512153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170256075 + 5170256076.

It is an arithmetic number, because the mean of its divisors is an integer number (5170256076).

Almost surely, 210340512151 is an apocalyptic number.

10340512151 is a deficient number, since it is larger than the sum of its proper divisors (1).

10340512151 is an equidigital number, since it uses as much as digits as its factorization.

10340512151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 23.

The spelling of 10340512151 in words is "ten billion, three hundred forty million, five hundred twelve thousand, one hundred fifty-one".