10341311333 has 4 divisors (see below), whose sum is σ = 10355420268. Its totient is φ = 10327202400.

The previous prime is 10341311303. The next prime is 10341311353. The reversal of 10341311333 is 33311314301.

10341311333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33311314301 = 76001 ⋅438301.

It can be written as a sum of positive squares in 2 ways, for example, as 8511354049 + 1829957284 = 92257^2 + 42778^2 .

It is a cyclic number.

It is not a de Polignac number, because 10341311333 - 2⁶ = 10341311269 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10341311299 and 10341311308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10341311303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7053368 + ... + 7054833.

It is an arithmetic number, because the mean of its divisors is an integer number (2588855067).

Almost surely, 2^10341311333 is an apocalyptic number.

It is an amenable number.

10341311333 is a deficient number, since it is larger than the sum of its proper divisors (14108935).

10341311333 is an equidigital number, since it uses as much as digits as its factorization.

10341311333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14108934.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 10341311333 its reverse (33311314301), we get a palindrome (43652625634).

The spelling of 10341311333 in words is "ten billion, three hundred forty-one million, three hundred eleven thousand, three hundred thirty-three".