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1034314430501 = 1194028584591
BaseRepresentation
bin11110000110100011111…
…00011011100000100101
310122212202011002002212102
433003101330123200211
5113421233443234001
62111054003501445
7134504163412322
oct17032174334045
93585664062772
101034314430501
11369717593470
12148559987885
13766c64634a1
14380bd893b49
151bd89024e6b
hexf0d1f1b825

1034314430501 has 4 divisors (see below), whose sum is σ = 1128343015104. Its totient is φ = 940285845900.

The previous prime is 1034314430477. The next prime is 1034314430579. The reversal of 1034314430501 is 1050344134301.

It is a happy number.

1034314430501 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1034314430501 is a prime.

It is a super-2 number, since 2×10343144305012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1034314433501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47014292285 + ... + 47014292306.

It is an arithmetic number, because the mean of its divisors is an integer number (282085753776).

Almost surely, 21034314430501 is an apocalyptic number.

1034314430501 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1034314430501 is a deficient number, since it is larger than the sum of its proper divisors (94028584603).

1034314430501 is an equidigital number, since it uses as much as digits as its factorization.

1034314430501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94028584602.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1034314430501 its reverse (1050344134301), we get a palindrome (2084658564802).

The spelling of 1034314430501 in words is "one trillion, thirty-four billion, three hundred fourteen million, four hundred thirty thousand, five hundred one".

Divisors: 1 11 94028584591 1034314430501