103642127 has 4 divisors (see below), whose sum is σ = 103683360. Its totient is φ = 103600896.

The previous prime is 103642109. The next prime is 103642129. The reversal of 103642127 is 721246301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 721246301 = 17 ⋅42426253.

It is a cyclic number.

It is not a de Polignac number, because 103642127 - 2¹⁰ = 103641103 is a prime.

It is a super-3 number, since 3×103642127³ (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103642096 and 103642105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103642129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16583 + ... + 21960.

It is an arithmetic number, because the mean of its divisors is an integer number (25920840).

Almost surely, 2^103642127 is an apocalyptic number.

103642127 is a deficient number, since it is larger than the sum of its proper divisors (41233).

103642127 is an equidigital number, since it uses as much as digits as its factorization.

103642127 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41232.

The product of its (nonzero) digits is 2016, while the sum is 26.

The square root of 103642127 is about 10180.4777392812. The cubic root of 103642127 is about 469.7269078973.

Adding to 103642127 its reverse (721246301), we get a palindrome (824888428).

The spelling of 103642127 in words is "one hundred three million, six hundred forty-two thousand, one hundred twenty-seven".