Base | Representation |
---|---|
bin | 11110010001010110111… |
… | …01101110111010000111 |
3 | 10200102201010220121012022 |
4 | 33020223131232322013 |
5 | 114020121443101411 |
6 | 2113453122513355 |
7 | 135100633115213 |
oct | 17105335567207 |
9 | 3612633817168 |
10 | 1040111300231 |
11 | 3711217934a3 |
12 | 1496b720585b |
13 | 7710b41a213 |
14 | 384ad707943 |
15 | 1c0c7dd5edb |
hex | f22b76ee87 |
1040111300231 has 2 divisors, whose sum is σ = 1040111300232. Its totient is φ = 1040111300230.
The previous prime is 1040111300201. The next prime is 1040111300257. The reversal of 1040111300231 is 1320031110401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1040111300231 - 214 = 1040111283847 is a prime.
It is a super-2 number, since 2×10401113002312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1040111300201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520055650115 + 520055650116.
It is an arithmetic number, because the mean of its divisors is an integer number (520055650116).
Almost surely, 21040111300231 is an apocalyptic number.
1040111300231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1040111300231 is an equidigital number, since it uses as much as digits as its factorization.
1040111300231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1040111300231 its reverse (1320031110401), we get a palindrome (2360142410632).
The spelling of 1040111300231 in words is "one trillion, forty billion, one hundred eleven million, three hundred thousand, two hundred thirty-one".
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