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104023000127 is a prime number
BaseRepresentation
bin110000011100001000…
…0010000010000111111
3100221111112121220221102
41200320100100100333
53201014342001002
6115442033523315
710341533624564
oct1407020202077
9327445556842
10104023000127
11401302a96a2
12181b111353b
139a6a124ca7
14506b48086b
152a8c504a02
hex183841043f

104023000127 has 2 divisors, whose sum is σ = 104023000128. Its totient is φ = 104023000126.

The previous prime is 104023000069. The next prime is 104023000129. The reversal of 104023000127 is 721000320401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104023000127 - 230 = 102949258303 is a prime.

It is a super-2 number, since 2×1040230001272 (a number of 23 digits) contains 22 as substring.

Together with 104023000129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 104023000099 and 104023000108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104023000129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52011500063 + 52011500064.

It is an arithmetic number, because the mean of its divisors is an integer number (52011500064).

Almost surely, 2104023000127 is an apocalyptic number.

104023000127 is a deficient number, since it is larger than the sum of its proper divisors (1).

104023000127 is an equidigital number, since it uses as much as digits as its factorization.

104023000127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 20.

Adding to 104023000127 its reverse (721000320401), we get a palindrome (825023320528).

The spelling of 104023000127 in words is "one hundred four billion, twenty-three million, one hundred twenty-seven", and thus it is an aban number.