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104033132117 is a prime number
BaseRepresentation
bin110000011100011011…
…0111001111001010101
3100221112020200200102022
41200320312321321111
53201024440211432
6115443035022525
710342016014115
oct1407066717125
9327466620368
10104033132117
1140135a99a42
12181b459aa45
139a6c261955
14506c95b045
152a8d356b12
hex1838db9e55

104033132117 has 2 divisors, whose sum is σ = 104033132118. Its totient is φ = 104033132116.

The previous prime is 104033132113. The next prime is 104033132143. The reversal of 104033132117 is 711231330401.

It is a happy number.

It is an a-pointer prime, because the next prime (104033132143) can be obtained adding 104033132117 to its sum of digits (26).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95381527921 + 8651604196 = 308839^2 + 93014^2 .

It is a cyclic number.

It is not a de Polignac number, because 104033132117 - 22 = 104033132113 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104033132113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52016566058 + 52016566059.

It is an arithmetic number, because the mean of its divisors is an integer number (52016566059).

Almost surely, 2104033132117 is an apocalyptic number.

It is an amenable number.

104033132117 is a deficient number, since it is larger than the sum of its proper divisors (1).

104033132117 is an equidigital number, since it uses as much as digits as its factorization.

104033132117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 104033132117 its reverse (711231330401), we get a palindrome (815264462518).

The spelling of 104033132117 in words is "one hundred four billion, thirty-three million, one hundred thirty-two thousand, one hundred seventeen".