10404040021133 has 4 divisors (see below), whose sum is σ = 11349861841248. Its totient is φ = 9458218201020.

The previous prime is 10404040021121. The next prime is 10404040021187. The reversal of 10404040021133 is 33112004040401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10404040021133 - 2¹² = 10404040017037 is a prime.

It is a super-2 number, since 2×10404040021133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10404040021099 and 10404040021108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10404040021103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 472910910041 + ... + 472910910062.

It is an arithmetic number, because the mean of its divisors is an integer number (2837465460312).

Almost surely, 2^{10404040021133} is an apocalyptic number.

It is an amenable number.

10404040021133 is a deficient number, since it is larger than the sum of its proper divisors (945821820115).

10404040021133 is an equidigital number, since it uses as much as digits as its factorization.

10404040021133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 945821820114.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10404040021133 its reverse (33112004040401), we get a palindrome (43516044061534).

The spelling of 10404040021133 in words is "ten trillion, four hundred four billion, forty million, twenty-one thousand, one hundred thirty-three".