Base | Representation |
---|---|
bin | 110000011100101001… |
… | …0101111111000001011 |
3 | 100221112202102111202120 |
4 | 1200321102233320023 |
5 | 3201033322243430 |
6 | 115443455302323 |
7 | 10342135034025 |
oct | 1407122577013 |
9 | 327482374676 |
10 | 104040431115 |
11 | 4013a124875 |
12 | 181b6b1a9a3 |
13 | 9a70918c9a |
14 | 506d8db015 |
15 | 2a8dce9610 |
hex | 18394afe0b |
104040431115 has 32 divisors (see below), whose sum is σ = 173782402560. Its totient is φ = 53051218176.
The previous prime is 104040431107. The next prime is 104040431141. The reversal of 104040431115 is 511134040401.
It is a happy number.
It is not a de Polignac number, because 104040431115 - 23 = 104040431107 is a prime.
It is a super-2 number, since 2×1040404311152 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 691591 + ... + 828479.
It is an arithmetic number, because the mean of its divisors is an integer number (5430700080).
Almost surely, 2104040431115 is an apocalyptic number.
104040431115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
104040431115 is a deficient number, since it is larger than the sum of its proper divisors (69741971445).
104040431115 is a wasteful number, since it uses less digits than its factorization.
104040431115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 139123.
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 104040431115 its reverse (511134040401), we get a palindrome (615174471516).
The spelling of 104040431115 in words is "one hundred four billion, forty million, four hundred thirty-one thousand, one hundred fifteen".
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