10412113 has 4 divisors (see below), whose sum is σ = 10418868. Its totient is φ = 10405360.

The previous prime is 10412111. The next prime is 10412117. The reversal of 10412113 is 31121401.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 1926544 + 8485569 = 1388^2 + 2913^2 .

It is a cyclic number.

It is not a de Polignac number, because 10412113 - 2¹ = 10412111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10412093 and 10412102.

It is not an unprimeable number, because it can be changed into a prime (10412111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195 + ... + 4567.

It is an arithmetic number, because the mean of its divisors is an integer number (2604717).

Almost surely, 2^10412113 is an apocalyptic number.

It is an amenable number.

10412113 is a deficient number, since it is larger than the sum of its proper divisors (6755).

10412113 is an equidigital number, since it uses as much as digits as its factorization.

10412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6754.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 10412113 is about 3226.7805937188. The cubic root of 10412113 is about 218.3632875917.

Adding to 10412113 its reverse (31121401), we get a palindrome (41533514).

The spelling of 10412113 in words is "ten million, four hundred twelve thousand, one hundred thirteen".