1041300100541 has 2 divisors, whose sum is σ = 1041300100542. Its totient is φ = 1041300100540.

The previous prime is 1041300100457. The next prime is 1041300100543. The reversal of 1041300100541 is 1450010031401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 595381992100 + 445918108441 = 771610^2 + 667771^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1041300100541 is a prime.

Together with 1041300100543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1041300100543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520650050270 + 520650050271.

It is an arithmetic number, because the mean of its divisors is an integer number (520650050271).

Almost surely, 2^{1041300100541} is an apocalyptic number.

It is an amenable number.

1041300100541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041300100541 is an equidigital number, since it uses as much as digits as its factorization.

1041300100541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 1041300100541 its reverse (1450010031401), we get a palindrome (2491310131942).

The spelling of 1041300100541 in words is "one trillion, forty-one billion, three hundred million, one hundred thousand, five hundred forty-one".