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1041300314143 = 1721605055383
BaseRepresentation
bin11110010011100100101…
…01011101100000011111
310200112210000020202122121
433021302111131200133
5114030040340023033
62114211115323411
7135142251426115
oct17116225354037
93615700222577
101041300314143
11371681976221
12149989450567
137726a86604b
14385835b7ab5
151c1474a162d
hexf27255d81f

1041300314143 has 4 divisors (see below), whose sum is σ = 1041905371248. Its totient is φ = 1040695257040.

The previous prime is 1041300314113. The next prime is 1041300314147. The reversal of 1041300314143 is 3414130031401.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1041300314143 - 29 = 1041300313631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1041300314147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302525971 + ... + 302529412.

It is an arithmetic number, because the mean of its divisors is an integer number (260476342812).

Almost surely, 21041300314143 is an apocalyptic number.

1041300314143 is a deficient number, since it is larger than the sum of its proper divisors (605057105).

1041300314143 is an equidigital number, since it uses as much as digits as its factorization.

1041300314143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 605057104.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1041300314143 its reverse (3414130031401), we get a palindrome (4455430345544).

The spelling of 1041300314143 in words is "one trillion, forty-one billion, three hundred million, three hundred fourteen thousand, one hundred forty-three".

Divisors: 1 1721 605055383 1041300314143