Search a number
-
+
104131127 is a prime number
BaseRepresentation
bin1100011010011…
…10101000110111
321020221102001102
412031032220313
5203124144002
614155520315
72403046202
oct615165067
9236842042
10104131127
1153863291
122aa5909b
131875bc69
14db88939
15921da02
hex634ea37

104131127 has 2 divisors, whose sum is σ = 104131128. Its totient is φ = 104131126.

The previous prime is 104131123. The next prime is 104131129. The reversal of 104131127 is 721131401.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104131127 - 22 = 104131123 is a prime.

It is a super-2 number, since 2×1041311272 = 21686583220580258, which contains 22 as substring.

Together with 104131129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 104131099 and 104131108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104131121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52065563 + 52065564.

It is an arithmetic number, because the mean of its divisors is an integer number (52065564).

Almost surely, 2104131127 is an apocalyptic number.

104131127 is a deficient number, since it is larger than the sum of its proper divisors (1).

104131127 is an equidigital number, since it uses as much as digits as its factorization.

104131127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 104131127 is about 10204.4660320861. The cubic root of 104131127 is about 470.4644977829.

Adding to 104131127 its reverse (721131401), we get a palindrome (825262528).

The spelling of 104131127 in words is "one hundred four million, one hundred thirty-one thousand, one hundred twenty-seven".