Base | Representation |
---|---|
bin | 10011011001011110… |
… | …11101101110110111 |
3 | 222212210101002110212 |
4 | 21230233131232313 |
5 | 132312031111341 |
6 | 4441222540035 |
7 | 516035141456 |
oct | 115457355667 |
9 | 28783332425 |
10 | 10414316471 |
11 | 4464679119 |
12 | 202789761b |
13 | c9c7a2250 |
14 | 70b1b2b9d |
15 | 40e44d5eb |
hex | 26cbddbb7 |
10414316471 has 4 divisors (see below), whose sum is σ = 11215417752. Its totient is φ = 9613215192.
The previous prime is 10414316431. The next prime is 10414316491. The reversal of 10414316471 is 17461341401.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10414316471 is a prime.
It is a super-3 number, since 3×104143164713 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10414316431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 400550621 + ... + 400550646.
It is an arithmetic number, because the mean of its divisors is an integer number (2803854438).
Almost surely, 210414316471 is an apocalyptic number.
10414316471 is a deficient number, since it is larger than the sum of its proper divisors (801101281).
10414316471 is an equidigital number, since it uses as much as digits as its factorization.
10414316471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 801101280.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 10414316471 its reverse (17461341401), we get a palindrome (27875657872).
The spelling of 10414316471 in words is "ten billion, four hundred fourteen million, three hundred sixteen thousand, four hundred seventy-one".
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