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10441312031 is a prime number
BaseRepresentation
bin10011011100101100…
…11100011100011111
3222221200011121102102
421232112130130133
5132340433441111
64444025315315
7516513454643
oct115626343437
928850147372
1010441312031
1144789372a7
122034935b3b
13ca5264857
147109dcc23
154119d213b
hex26e59c71f

10441312031 has 2 divisors, whose sum is σ = 10441312032. Its totient is φ = 10441312030.

The previous prime is 10441312019. The next prime is 10441312033. The reversal of 10441312031 is 13021314401.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10441312031 is a prime.

It is a super-2 number, since 2×104413120312 (a number of 21 digits) contains 22 as substring.

Together with 10441312033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10441311994 and 10441312012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10441312033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5220656015 + 5220656016.

It is an arithmetic number, because the mean of its divisors is an integer number (5220656016).

Almost surely, 210441312031 is an apocalyptic number.

10441312031 is a deficient number, since it is larger than the sum of its proper divisors (1).

10441312031 is an equidigital number, since it uses as much as digits as its factorization.

10441312031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10441312031 its reverse (13021314401), we get a palindrome (23462626432).

The spelling of 10441312031 in words is "ten billion, four hundred forty-one million, three hundred twelve thousand, thirty-one".