Base | Representation |
---|---|
bin | 110000111010010001… |
… | …0011100001010011011 |
3 | 101001010000202101022012 |
4 | 1201310202130022123 |
5 | 3210102301303121 |
6 | 120130243420135 |
7 | 10405564446503 |
oct | 1416442341233 |
9 | 331100671265 |
10 | 105034400411 |
11 | 405aa1a96a6 |
12 | 1843398464b |
13 | 9b9b8241b5 |
14 | 5125918a03 |
15 | 2aeb1d8c5b |
hex | 187489c29b |
105034400411 has 2 divisors, whose sum is σ = 105034400412. Its totient is φ = 105034400410.
The previous prime is 105034400389. The next prime is 105034400413. The reversal of 105034400411 is 114004430501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 105034400411 - 218 = 105034138267 is a prime.
It is a super-2 number, since 2×1050344004112 (a number of 23 digits) contains 22 as substring.
Together with 105034400413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (105034400413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52517200205 + 52517200206.
It is an arithmetic number, because the mean of its divisors is an integer number (52517200206).
Almost surely, 2105034400411 is an apocalyptic number.
105034400411 is a deficient number, since it is larger than the sum of its proper divisors (1).
105034400411 is an equidigital number, since it uses as much as digits as its factorization.
105034400411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 105034400411 its reverse (114004430501), we get a palindrome (219038830912).
The spelling of 105034400411 in words is "one hundred five billion, thirty-four million, four hundred thousand, four hundred eleven".
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