Base | Representation |
---|---|
bin | 10011100101001001… |
… | …00001011011000100 |
3 | 1000010121101120202120 |
4 | 21302210201123010 |
5 | 133012100030200 |
6 | 4455035005540 |
7 | 521333320545 |
oct | 116244413304 |
9 | 30117346676 |
10 | 10512111300 |
11 | 45048a3899 |
12 | 20545998b0 |
13 | cb6b23102 |
14 | 71a18c4cc |
15 | 417d199a0 |
hex | 2729216c4 |
10512111300 has 144 divisors (see below), whose sum is σ = 31031347200. Its totient is φ = 2746972800.
The previous prime is 10512111293. The next prime is 10512111307. The reversal of 10512111300 is 311121501.
It is an interprime number because it is at equal distance from previous prime (10512111293) and next prime (10512111307).
It is a super-2 number, since 2×105121113002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 10512111300.
It is not an unprimeable number, because it can be changed into a prime (10512111307) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3292705 + ... + 3295895.
Almost surely, 210512111300 is an apocalyptic number.
10512111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 10512111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15515673600).
10512111300 is an abundant number, since it is smaller than the sum of its proper divisors (20519235900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10512111300 is a wasteful number, since it uses less digits than its factorization.
10512111300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3426 (or 3419 counting only the distinct ones).
The product of its (nonzero) digits is 30, while the sum is 15.
Adding to 10512111300 its reverse (311121501), we get a palindrome (10823232801).
The spelling of 10512111300 in words is "ten billion, five hundred twelve million, one hundred eleven thousand, three hundred".
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