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10512111300 = 22352791393191
BaseRepresentation
bin10011100101001001…
…00001011011000100
31000010121101120202120
421302210201123010
5133012100030200
64455035005540
7521333320545
oct116244413304
930117346676
1010512111300
1145048a3899
1220545998b0
13cb6b23102
1471a18c4cc
15417d199a0
hex2729216c4

10512111300 has 144 divisors (see below), whose sum is σ = 31031347200. Its totient is φ = 2746972800.

The previous prime is 10512111293. The next prime is 10512111307. The reversal of 10512111300 is 311121501.

It is an interprime number because it is at equal distance from previous prime (10512111293) and next prime (10512111307).

It is a super-2 number, since 2×105121113002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 10512111300.

It is not an unprimeable number, because it can be changed into a prime (10512111307) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3292705 + ... + 3295895.

Almost surely, 210512111300 is an apocalyptic number.

10512111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10512111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15515673600).

10512111300 is an abundant number, since it is smaller than the sum of its proper divisors (20519235900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10512111300 is a wasteful number, since it uses less digits than its factorization.

10512111300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3426 (or 3419 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 15.

Adding to 10512111300 its reverse (311121501), we get a palindrome (10823232801).

The spelling of 10512111300 in words is "ten billion, five hundred twelve million, one hundred eleven thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 79 100 139 150 158 237 278 300 316 395 417 474 556 695 790 834 948 1185 1390 1580 1668 1975 2085 2370 2780 3191 3475 3950 4170 4740 5925 6382 6950 7900 8340 9573 10425 10981 11850 12764 13900 15955 19146 20850 21962 23700 31910 32943 38292 41700 43924 47865 54905 63820 65886 79775 95730 109810 131772 159550 164715 191460 219620 239325 252089 274525 319100 329430 443549 478650 504178 549050 658860 756267 823575 887098 957300 1008356 1098100 1260445 1330647 1512534 1647150 1774196 2217745 2520890 2661294 3025068 3294300 3781335 4435490 5041780 5322588 6302225 6653235 7562670 8870980 11088725 12604450 13306470 15125340 18906675 22177450 25208900 26612940 33266175 35040371 37813350 44354900 66532350 70080742 75626700 105121113 133064700 140161484 175201855 210242226 350403710 420484452 525605565 700807420 876009275 1051211130 1752018550 2102422260 2628027825 3504037100 5256055650 10512111300