Base | Representation |
---|---|
bin | 110000111101100001… |
… | …0010111011110101100 |
3 | 101001101121220211002010 |
4 | 1201323002113132230 |
5 | 3210313204330012 |
6 | 120145140401220 |
7 | 10411360302243 |
oct | 1417302273654 |
9 | 331347824063 |
10 | 105143433132 |
11 | 406557aa591 |
12 | 184643a6210 |
13 | 9bb82ab1ba |
14 | 51361bb95a |
15 | 2b05a74c3c |
hex | 187b0977ac |
105143433132 has 48 divisors (see below), whose sum is σ = 247141198080. Its totient is φ = 34790311872.
The previous prime is 105143433113. The next prime is 105143433149. The reversal of 105143433132 is 231334341501.
It is a happy number.
It is a super-2 number, since 2×1051434331322 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 105143433132.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1445458 + ... + 1516454.
It is an arithmetic number, because the mean of its divisors is an integer number (5148774960).
Almost surely, 2105143433132 is an apocalyptic number.
105143433132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
105143433132 is an abundant number, since it is smaller than the sum of its proper divisors (141997764948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
105143433132 is a wasteful number, since it uses less digits than its factorization.
105143433132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71910 (or 71908 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 105143433132 its reverse (231334341501), we get a palindrome (336477774633).
The spelling of 105143433132 in words is "one hundred five billion, one hundred forty-three million, four hundred thirty-three thousand, one hundred thirty-two".
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