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10516433113550 = 2527313226720807
BaseRepresentation
bin1001100100001000110001…
…0000101001000111001110
31101020100202022020121222002
42121002030100221013032
52334300123334113200
634211103242552302
72133534005363000
oct231021420510716
941210668217862
1010516433113550
113394aa33699a1
12121a1a4208692
135b39069c6010
14284dd8a28370
151338535c1bd5
hex9908c4291ce

10516433113550 has 192 divisors, whose sum is σ = 24577876915200. Its totient is φ = 3326649701760.

The previous prime is 10516433113541. The next prime is 10516433113583. The reversal of 10516433113550 is 5531133461501.

It is a super-2 number, since 2×105164331135502 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 505417247 + ... + 505438053.

It is an arithmetic number, because the mean of its divisors is an integer number (128009775600).

Almost surely, 210516433113550 is an apocalyptic number.

10516433113550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10516433113550 is an abundant number, since it is smaller than the sum of its proper divisors (14061443801650).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10516433113550 is a wasteful number, since it uses less digits than its factorization.

10516433113550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23120 (or 23101 counting only the distinct ones).

The product of its (nonzero) digits is 81000, while the sum is 38.

The spelling of 10516433113550 in words is "ten trillion, five hundred sixteen billion, four hundred thirty-three million, one hundred thirteen thousand, five hundred fifty".