Base | Representation |
---|---|
bin | 11110100111100100001… |
… | …11110100001001100111 |
3 | 10201120111001212101100002 |
4 | 33103302013310021213 |
5 | 114214031220430421 |
6 | 2123144155011515 |
7 | 136002246526112 |
oct | 17236207641147 |
9 | 3646431771302 |
10 | 1052034155111 |
11 | 37618a943875 |
12 | 14ba84139b9b |
13 | 7828b5b0c34 |
14 | 38cc0da3579 |
15 | 1c5749b8b0b |
hex | f4f21f4267 |
1052034155111 has 2 divisors, whose sum is σ = 1052034155112. Its totient is φ = 1052034155110.
The previous prime is 1052034155101. The next prime is 1052034155113. The reversal of 1052034155111 is 1115514302501.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1052034155111 is a prime.
It is a super-2 number, since 2×10520341551112 (a number of 25 digits) contains 22 as substring.
Together with 1052034155113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1052034155113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526017077555 + 526017077556.
It is an arithmetic number, because the mean of its divisors is an integer number (526017077556).
Almost surely, 21052034155111 is an apocalyptic number.
1052034155111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1052034155111 is an equidigital number, since it uses as much as digits as its factorization.
1052034155111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 29.
Adding to 1052034155111 its reverse (1115514302501), we get a palindrome (2167548457612).
The spelling of 1052034155111 in words is "one trillion, fifty-two billion, thirty-four million, one hundred fifty-five thousand, one hundred eleven".
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