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105243911 is a prime number
BaseRepresentation
bin1100100010111…
…10010100000111
321100000221111122
412101132110013
5203420301121
614235424155
72415362363
oct621362407
9240027448
10105243911
1154453343
122b2b505b
1318a5b606
14dd982a3
15938d5ab
hex645e507

105243911 has 2 divisors, whose sum is σ = 105243912. Its totient is φ = 105243910.

The previous prime is 105243893. The next prime is 105243913. The reversal of 105243911 is 119342501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 105243911 - 214 = 105227527 is a prime.

It is a super-3 number, since 3×1052439113 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 105243913, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105243913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52621955 + 52621956.

It is an arithmetic number, because the mean of its divisors is an integer number (52621956).

Almost surely, 2105243911 is an apocalyptic number.

105243911 is a deficient number, since it is larger than the sum of its proper divisors (1).

105243911 is an equidigital number, since it uses as much as digits as its factorization.

105243911 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 26.

The square root of 105243911 is about 10258.8455003475. The cubic root of 105243911 is about 472.1344163160.

The spelling of 105243911 in words is "one hundred five million, two hundred forty-three thousand, nine hundred eleven".