1053315131 has 4 divisors (see below), whose sum is σ = 1149071064. Its totient is φ = 957559200.

The previous prime is 1053315127. The next prime is 1053315157. The reversal of 1053315131 is 1315133501.

1053315131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1053315131 - 2² = 1053315127 is a prime.

It is a super-2 number, since 2×1053315131² = 2218945530387094322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1053315097 and 1053315106.

It is not an unprimeable number, because it can be changed into a prime (1053315181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47877950 + ... + 47877971.

It is an arithmetic number, because the mean of its divisors is an integer number (287267766).

Almost surely, 2^1053315131 is an apocalyptic number.

1053315131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1053315131 is a deficient number, since it is larger than the sum of its proper divisors (95755933).

1053315131 is an equidigital number, since it uses as much as digits as its factorization.

1053315131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95755932.

The product of its (nonzero) digits is 675, while the sum is 23.

The square root of 1053315131 is about 32454.8167611527. The cubic root of 1053315131 is about 1017.4649114668.

Adding to 1053315131 its reverse (1315133501), we get a palindrome (2368448632).

The spelling of 1053315131 in words is "one billion, fifty-three million, three hundred fifteen thousand, one hundred thirty-one".